Robust perfect adaptation in
A with
Aset = 1.0. (
a) Model described in Fig. 3
a with rate constants as given in the Appendix. At
t = 5.0 time units,
kpert is increased from 0.0 to 1.0. (
b) Initial conditions as given in the Appendix with
kpert = 1.0. At
t = 5.0 time units,
kpert is increased from 1.0 to 10
3 a.u. (
c) Initial conditions as in panel
b. At
t = 5.0 time units,
kpert is decreased from 1.0 to 10
−3 a.u. (
d) Same initial conditions as in panel
b, but
Etr is successively increased leading eventually to the breakdown in homeostasis indicated by the decreasing
Ass values. This breakdown can be opposed to a certain degree by increasing the values of
kpert or
ksynth. In the figure,
kpert or
ksynth were increased from their original values 1.0 and 3.0 to 10.0 and 12.0, respectively, thereby extending the homeostasis to larger
Etr values (
dashed line). However, at higher
Etr concentrations the homeostasis fails again with decreasing
Ass values (data not shown). (
e) Calculated
Ass values for varying

with
ksynth = 3.0 a.u. and
kpert = 1.0 a.u. (
solid circles), or with
ksynth = 3.0 a.u. and
kpert = 5.0 a.u. (
open circles). For

< 10
9 a.u., perfect homeostasis in
A is lost (indicated by the condition that
Ass <
Aset), because for decreasing

the

associated with the removal of
Eadapt by
Eset increases, which eventually leads to the loss of the zero-order kinetics in the
Eadapt degradation. (
f) Time profiles in
A with two different

values. At
t = 5.0 time units,
kpert is increased from 1.0 to 5.0 a.u. 1 = Perfect homeostasis in
A for

= 10
12 a.u.; 2 = Loss of perfect homeostasis in
A when

= 10
6 a.u., which is due to the loss of zero-order kinetics in the degradation of
Eadapt.